Write a Program to Implement Travelling Salesman Problem using Python.
SOURCE CODE :
from collections import deque
def tsp_bfs(graph):
n = len(graph) # Number of cities
startCity = 0 # Starting city
min_cost = float('inf') # Initialize minimum cost as infinity
opt_path = [] # To store the optimal path
# Queue for BFS: Each element is (cur_path, cur_cost)
dq = deque([([startCity], 0)])
print("Path Traversal:")
while dq:
cur_path, cur_cost = dq.popleft()
cur_city = cur_path[-1]
# Print the current path and cost
print(f"Current Path: {cur_path}, Current Cost: {cur_cost}")
# If all cities are visited and we are back at the startCity
if len(cur_path) == n and cur_path[0] == startCity:
total_cost = cur_cost + graph[cur_city][startCity]
if total_cost < min_cost:
min_cost = total_cost
opt_path = cur_path + [startCity]
continue
# Explore all neighboring cities (add in BFS manner)
for next_city in range(n):
if next_city not in cur_path: # Visit unvisited cities
new_path = cur_path + [next_city]
new_cost = cur_cost + graph[cur_city][next_city]
dq.append((new_path, new_cost))
return min_cost, opt_path
# Example graph as a 2D adjacency matrix
graph = [
[0, 10, 15, 20],
[10, 0, 35, 25],
[15, 35, 0, 30],
[20, 25, 30, 0]
]
# Solve TSP using BFS
min_cost, opt_path = tsp_bfs(graph)
print("\nOptimal Solution:")
print(f"Minimum cost: {min_cost}")
print(f"Optimal path: {opt_path}")
OUTPUT :
Path Traversal:
Current Path: [0], Current Cost: 0
Current Path: [0, 1], Current Cost: 10
Current Path: [0, 2], Current Cost: 15
Current Path: [0, 3], Current Cost: 20
Current Path: [0, 1, 2], Current Cost: 45
Current Path: [0, 1, 3], Current Cost: 35
Current Path: [0, 2, 1], Current Cost: 50
Current Path: [0, 2, 3], Current Cost: 45
Current Path: [0, 3, 1], Current Cost: 45
Current Path: [0, 3, 2], Current Cost: 50
Current Path: [0, 1, 2, 3], Current Cost: 75
Current Path: [0, 1, 3, 2], Current Cost: 65
Current Path: [0, 2, 1, 3], Current Cost: 75
Current Path: [0, 2, 3, 1], Current Cost: 70
Current Path: [0, 3, 1, 2], Current Cost: 80
Current Path: [0, 3, 2, 1], Current Cost: 85
Optimal Solution:
Minimum cost: 80
Optimal path: [0, 1, 3, 2, 0]
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